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javascript Mutations

 Return true if the string in the first element of the array contains all of the letters of the string in the second element of the array.


For example, ["hello", "Hello"], should return true because all of the letters in the second string are present in the first, ignoring case.


The arguments ["hello", "hey"] should return false because the string hello does not contain a y.


Lastly, ["Alien", "line"], should return true because all of the letters in line are present in Alien.


function mutation(arr) {
  var temArr =[];
  for(let i=0;i<arr[1].length;i++)//要比较的是第二个数组的,所以放在外层,内层每次都要遍历第一个数组,让第二个数组中的字符去与每一个第一个数组中的字符比较,相等就push一个true,然后马上跳出内循环
  {
    for (let j=0;j<arr[0].length;j++)
    {
      if (arr[1][i].toUpperCase()==arr[0][j].toUpperCase())
      {
        temArr.push(true);
        break;//这个跳出很重要,如果继续循环,后来又比对成功,再push一个true就会导致我们的标志length不同
      }
    }

  }
  console.log(temArr.length);
  console.log(arr[1].length);
  if (temArr.length == arr[1].length)//说明每个元素都找到了,都包含
  {
    return true;
  }
  return false;
}

mutation(["hello""hey"]);

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